(3x-5)/2-(4x-2)/5=3x/10-2+(2^-1)(x-23)

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Solution for (3x-5)/2-(4x-2)/5=3x/10-2+(2^-1)(x-23) equation: 



(3x-5)/2-(4x-2)/5=3x/10-2+(2^-1)(x-23)

We move all terms to the left:

(3x-5)/2-(4x-2)/5-(3x/10-2+(2^-1)(x-23))=0



Domain of the equation: 10-2+(2^-1)(x-23))!=0

We move all terms containing x to the left, all other terms to the right

(2^-1)(x-23))!=-8

x∈R



We calculate fractions


((3x-5)*5*10+(2^-1)(x-23))-2)/((2^-1)(x-23))-2+2*5*10)+(-(4x-1)(x-23))-2)/((2^-1)(x-23))-2+2*5*10)+(-(3x*2*5)/((2^-1)(x-23))-2+2*5*10)-2)*2*10+(2^=0



We calculate terms in parentheses: +((3x-5)*5*10+(2^-1)(x-23)), so:

(3x-5)*5*10+(2^-1)(x-23)



We can not solve this equation

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